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Improved functional form for $f$ -- method of Methfessel and Paxton


Table 2: Typical convenient settings for $sigma$ for different metals: Aluminium possesses an extremely simple DOS, Lithium and Tellurium are also simple nearly free electron metals, therefore $sigma$ might be large. For Copper $sigma$ is restricted by the fact that the d-band lies approximately 0.5 eV beneath the Fermi-level. Rhodium and Vanadium posses a fairly complex structure in the DOS at the Fermi-level, $sigma$ must be small.
  Sigma (eV)
Aluminium $ 1.0 $
Lithium 0.4
Tellurium 0.8
Copper, Palladium 0.4
Vanadium 0.2
Rhodium 0.2
Potassium 0.3

The method described in the last section has two shortcomings:

These problems can be solved by adopting a slightly different functional form for $f(\{\epsilon _{n{\bf k}}\})$. This is possible by expanding the step function in a complete orthonormal set of functions (method of Methfessel and Paxton [36]). The Gaussian function is only the first approximation (N=0) to the step function, further successive approximations (N=1,2,...) are easily obtained. In similarity to the Gaussian method, the energy has to be replaced by a generalized free energy functional

\begin{displaymath}\vspace*{1mm}
F =E - \sum_{n{\bf k}}w_{\bf k}\sigma S(f_{n{\bf k}}).
\end{displaymath}


In contrast to the Gaussian method the entropy term $\sum_{n{\bf k}}w_{\bf k}\sigma S(f_{n{\bf k}})$ will be very small for reasonable values of $sigma$ (for instance for the values given in table 2). The $\sum_{n{\bf k}}w_{\bf k}\sigma S(f_{n{\bf k}})$ is a simple error estimation for the difference between the free energy $F$ and the 'physical' energy $E(\sigma \to 0)$. $sigma$ can be increased till this error estimation gets too large.


next up previous contents
Next: Forces Up: Partial occupancies, different methods Previous: Finite temperature approaches   Contents
Georg Kresse
2009-04-23